Base | Representation |
---|---|
bin | 1010000110110111110000… |
… | …0001010001011110110011 |
3 | 1110100102000022020100011212 |
4 | 2201231330001101132303 |
5 | 2424034223220301113 |
6 | 35345152110430335 |
7 | 2224620330532331 |
oct | 241557401213663 |
9 | 43312008210155 |
10 | 11113161103283 |
11 | 35a50797a5778 |
12 | 12b597b2023ab |
13 | 627c747c1175 |
14 | 2a5c464dab51 |
15 | 14412b06a0a8 |
hex | a1b7c0517b3 |
11113161103283 has 2 divisors, whose sum is σ = 11113161103284. Its totient is φ = 11113161103282.
The previous prime is 11113161103271. The next prime is 11113161103301. The reversal of 11113161103283 is 38230116131111.
11113161103283 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11113161103283 - 238 = 10838283196339 is a prime.
It is not a weakly prime, because it can be changed into another prime (11113161103243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556580551641 + 5556580551642.
It is an arithmetic number, because the mean of its divisors is an integer number (5556580551642).
Almost surely, 211113161103283 is an apocalyptic number.
11113161103283 is a deficient number, since it is larger than the sum of its proper divisors (1).
11113161103283 is an equidigital number, since it uses as much as digits as its factorization.
11113161103283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 32.
Adding to 11113161103283 its reverse (38230116131111), we get a palindrome (49343277234394).
The spelling of 11113161103283 in words is "eleven trillion, one hundred thirteen billion, one hundred sixty-one million, one hundred three thousand, two hundred eighty-three".
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