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11113316254113 = 33704438751371
BaseRepresentation
bin1010000110111000010101…
…0001001000000110100001
31110100102102010011211002220
42201232011101020012201
52424040032430112423
635345215332101253
72224624223354163
oct241560521100641
943312363154086
1011113316254113
1135a51493358a7
1212b5a03164829
13627c9a9a46a8
142a5c5cd66933
151441399b59e3
hexa1b854481a1

11113316254113 has 4 divisors (see below), whose sum is σ = 14817755005488. Its totient is φ = 7408877502740.

The previous prime is 11113316254111. The next prime is 11113316254121. The reversal of 11113316254113 is 31145261331111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11113316254113 - 21 = 11113316254111 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11113316254111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1852219375683 + ... + 1852219375688.

It is an arithmetic number, because the mean of its divisors is an integer number (3704438751372).

Almost surely, 211113316254113 is an apocalyptic number.

It is an amenable number.

11113316254113 is a deficient number, since it is larger than the sum of its proper divisors (3704438751375).

11113316254113 is an equidigital number, since it uses as much as digits as its factorization.

11113316254113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3704438751374.

The product of its digits is 6480, while the sum is 33.

Adding to 11113316254113 its reverse (31145261331111), we get a palindrome (42258577585224).

The spelling of 11113316254113 in words is "eleven trillion, one hundred thirteen billion, three hundred sixteen million, two hundred fifty-four thousand, one hundred thirteen".

Divisors: 1 3 3704438751371 11113316254113