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11113332320113 is a prime number
BaseRepresentation
bin1010000110111000011000…
…1110011010011101110001
31110100102110020102001111221
42201232012032122131301
52424040101033220423
635345221104305041
72224624510046632
oct241560616323561
943312406361457
1011113332320113
1135a5157409491
1212b5a08612181
13627ca110b2ba
142a5c61149889
1514413b0dae5d
hexa1b8639a771

11113332320113 has 2 divisors, whose sum is σ = 11113332320114. Its totient is φ = 11113332320112.

The previous prime is 11113332320099. The next prime is 11113332320119. The reversal of 11113332320113 is 31102323331111.

11113332320113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8937421160704 + 2175911159409 = 2989552^2 + 1475097^2 .

It is a cyclic number.

It is not a de Polignac number, because 11113332320113 - 217 = 11113332189041 is a prime.

It is not a weakly prime, because it can be changed into another prime (11113332320119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556666160056 + 5556666160057.

It is an arithmetic number, because the mean of its divisors is an integer number (5556666160057).

Almost surely, 211113332320113 is an apocalyptic number.

It is an amenable number.

11113332320113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11113332320113 is an equidigital number, since it uses as much as digits as its factorization.

11113332320113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 11113332320113 its reverse (31102323331111), we get a palindrome (42215655651224).

The spelling of 11113332320113 in words is "eleven trillion, one hundred thirteen billion, three hundred thirty-two million, three hundred twenty thousand, one hundred thirteen".