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11113444456657 is a prime number
BaseRepresentation
bin1010000110111000110011…
…1010001011100011010001
31110100102202001102011221021
42201232030322023203101
52424040313240103112
635345240151555441
72224630341150424
oct241561472134321
943312661364837
1011113444456657
1135a520473a314
1212b5a3a08bb81
13627cbb410c9a
142a5c71db99bb
15144145d8b907
hexa1b8ce8b8d1

11113444456657 has 2 divisors, whose sum is σ = 11113444456658. Its totient is φ = 11113444456656.

The previous prime is 11113444456651. The next prime is 11113444456661. The reversal of 11113444456657 is 75665444431111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10537061335056 + 576383121601 = 3246084^2 + 759199^2 .

It is an emirp because it is prime and its reverse (75665444431111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11113444456657 - 219 = 11113443932369 is a prime.

It is not a weakly prime, because it can be changed into another prime (11113444456651) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556722228328 + 5556722228329.

It is an arithmetic number, because the mean of its divisors is an integer number (5556722228329).

Almost surely, 211113444456657 is an apocalyptic number.

It is an amenable number.

11113444456657 is a deficient number, since it is larger than the sum of its proper divisors (1).

11113444456657 is an equidigital number, since it uses as much as digits as its factorization.

11113444456657 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4838400, while the sum is 52.

Adding to 11113444456657 its reverse (75665444431111), we get a palindrome (86778888887768).

The spelling of 11113444456657 in words is "eleven trillion, one hundred thirteen billion, four hundred forty-four million, four hundred fifty-six thousand, six hundred fifty-seven".