Base | Representation |
---|---|
bin | 1010000110111001000110… |
… | …0010000010010011011001 |
3 | 1110100102221110100110210021 |
4 | 2201232101202002103121 |
5 | 2424040443113412101 |
6 | 35345252002150441 |
7 | 2224632302316403 |
oct | 241562142022331 |
9 | 43312843313707 |
10 | 11113522013401 |
11 | 35a52444a18a5 |
12 | 12b5a60052421 |
13 | 6280014c7252 |
14 | 2a5c7c407b73 |
15 | 14414caab5a1 |
hex | a1b918824d9 |
11113522013401 has 4 divisors (see below), whose sum is σ = 11113540742052. Its totient is φ = 11113503284752.
The previous prime is 11113522013369. The next prime is 11113522013501. The reversal of 11113522013401 is 10431022531111.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 6207846318025 + 4905675695376 = 2491555^2 + 2214876^2 .
It is a cyclic number.
It is not a de Polignac number, because 11113522013401 - 25 = 11113522013369 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11113522013101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8444086 + ... + 9671071.
It is an arithmetic number, because the mean of its divisors is an integer number (2778385185513).
Almost surely, 211113522013401 is an apocalyptic number.
It is an amenable number.
11113522013401 is a deficient number, since it is larger than the sum of its proper divisors (18728651).
11113522013401 is an equidigital number, since it uses as much as digits as its factorization.
11113522013401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18728650.
The product of its (nonzero) digits is 720, while the sum is 25.
Adding to 11113522013401 its reverse (10431022531111), we get a palindrome (21544544544512).
The spelling of 11113522013401 in words is "eleven trillion, one hundred thirteen billion, five hundred twenty-two million, thirteen thousand, four hundred one".
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