Base | Representation |
---|---|
bin | 1010000110111010111101… |
… | …0010110010100000000001 |
3 | 1110100111020020220112111111 |
4 | 2201232233102302200001 |
5 | 2424043003430123433 |
6 | 35345413320243321 |
7 | 2224650544420555 |
oct | 241565722624001 |
9 | 43314206815444 |
10 | 11114021332993 |
11 | 35a5480334017 |
12 | 12b5b7b310541 |
13 | 628080aa1727 |
14 | 2a5cc8863865 |
15 | 14417b83cdcd |
hex | a1baf4b2801 |
11114021332993 has 2 divisors, whose sum is σ = 11114021332994. Its totient is φ = 11114021332992.
The previous prime is 11114021332987. The next prime is 11114021333081. The reversal of 11114021332993 is 39923312041111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10241388847089 + 872632485904 = 3200217^2 + 934148^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11114021332993 is a prime.
It is not a weakly prime, because it can be changed into another prime (11114021332943) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5557010666496 + 5557010666497.
It is an arithmetic number, because the mean of its divisors is an integer number (5557010666497).
Almost surely, 211114021332993 is an apocalyptic number.
It is an amenable number.
11114021332993 is a deficient number, since it is larger than the sum of its proper divisors (1).
11114021332993 is an equidigital number, since it uses as much as digits as its factorization.
11114021332993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 34992, while the sum is 40.
The spelling of 11114021332993 in words is "eleven trillion, one hundred fourteen billion, twenty-one million, three hundred thirty-two thousand, nine hundred ninety-three".
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