111140241023113 has 4 divisors (see below), whose sum is σ = 111605262952320. Its totient is φ = 110675219093908.

The previous prime is 111140241023081. The next prime is 111140241023129. The reversal of 111140241023113 is 311320142041111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 111140241023113 - 2⁵ = 111140241023081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (111140241063113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 232510964245 + ... + 232510964722.

It is an arithmetic number, because the mean of its divisors is an integer number (27901315738080).

Almost surely, 2^{111140241023113} is an apocalyptic number.

It is an amenable number.

111140241023113 is a deficient number, since it is larger than the sum of its proper divisors (465021929207).

111140241023113 is an equidigital number, since it uses as much as digits as its factorization.

111140241023113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 465021929206.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 111140241023113 its reverse (311320142041111), we get a palindrome (422460383064224).

The spelling of 111140241023113 in words is "one hundred eleven trillion, one hundred forty billion, two hundred forty-one million, twenty-three thousand, one hundred thirteen".