Base | Representation |
---|---|
bin | 110011110000001111… |
… | …0110000011010111001 |
3 | 101121212120011022201222 |
4 | 1213200132300122321 |
5 | 3310103411411213 |
6 | 123020203121425 |
7 | 11013106213022 |
oct | 1474036603271 |
9 | 347776138658 |
10 | 111140341433 |
11 | 43152909550 |
12 | 19658813275 |
13 | a632833954 |
14 | 5544823c49 |
15 | 2d5729b808 |
hex | 19e07b06b9 |
111140341433 has 16 divisors (see below), whose sum is σ = 121493718720. Its totient is φ = 100828761600.
The previous prime is 111140341427. The next prime is 111140341439. The reversal of 111140341433 is 334143041111.
It is an interprime number because it is at equal distance from previous prime (111140341427) and next prime (111140341439).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111140341433 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (111140341439) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20127713 + ... + 20133233.
It is an arithmetic number, because the mean of its divisors is an integer number (7593357420).
Almost surely, 2111140341433 is an apocalyptic number.
It is an amenable number.
111140341433 is a deficient number, since it is larger than the sum of its proper divisors (10353377287).
111140341433 is a wasteful number, since it uses less digits than its factorization.
111140341433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8968.
The product of its (nonzero) digits is 1728, while the sum is 26.
Adding to 111140341433 its reverse (334143041111), we get a palindrome (445283382544).
The spelling of 111140341433 in words is "one hundred eleven billion, one hundred forty million, three hundred forty-one thousand, four hundred thirty-three".
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