11114040331 has 2 divisors, whose sum is σ = 11114040332. Its totient is φ = 11114040330.

The previous prime is 11114040323. The next prime is 11114040341. The reversal of 11114040331 is 13304041111.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11114040331 - 2³ = 11114040323 is a prime.

It is a super-2 number, since 2×11114040331² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11114040299 and 11114040308.

It is not a weakly prime, because it can be changed into another prime (11114040341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5557020165 + 5557020166.

It is an arithmetic number, because the mean of its divisors is an integer number (5557020166).

Almost surely, 2^11114040331 is an apocalyptic number.

11114040331 is a deficient number, since it is larger than the sum of its proper divisors (1).

11114040331 is an equidigital number, since it uses as much as digits as its factorization.

11114040331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 11114040331 its reverse (13304041111), we get a palindrome (24418081442).

The spelling of 11114040331 in words is "eleven billion, one hundred fourteen million, forty thousand, three hundred thirty-one".