11114343111041 has 4 divisors (see below), whose sum is σ = 11115210009684. Its totient is φ = 11113476212400.

The previous prime is 11114343111037. The next prime is 11114343111049. The reversal of 11114343111041 is 14011134341111.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2782460861041 + 8331882250000 = 1668071^2 + 2886500^2 .

It is a cyclic number.

It is not a de Polignac number, because 11114343111041 - 2² = 11114343111037 is a prime.

It is a super-2 number, since 2×11114343111041² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11114343111041.

It is not an unprimeable number, because it can be changed into a prime (11114343111049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 433430090 + ... + 433455731.

It is an arithmetic number, because the mean of its divisors is an integer number (2778802502421).

Almost surely, 2^{11114343111041} is an apocalyptic number.

It is an amenable number.

11114343111041 is a deficient number, since it is larger than the sum of its proper divisors (866898643).

11114343111041 is an equidigital number, since it uses as much as digits as its factorization.

11114343111041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 866898642.

The product of its (nonzero) digits is 576, while the sum is 26.

Adding to 11114343111041 its reverse (14011134341111), we get a palindrome (25125477452152).

The spelling of 11114343111041 in words is "eleven trillion, one hundred fourteen billion, three hundred forty-three million, one hundred eleven thousand, forty-one".