Base | Representation |
---|---|
bin | 11001010001010111000011… |
… | …000010110100010100110011 |
3 | 112120112021110021201102002011 |
4 | 121101113003002310110303 |
5 | 104031441200044424243 |
6 | 1032214525152303351 |
7 | 32260620265625134 |
oct | 3121270302642463 |
9 | 476467407642064 |
10 | 111144141014323 |
11 | 32460a6909860a |
12 | 1057058bb41b57 |
13 | 4a02b03024601 |
14 | 1d63595955c8b |
15 | ccb1aa4c789d |
hex | 6515c30b4533 |
111144141014323 has 2 divisors, whose sum is σ = 111144141014324. Its totient is φ = 111144141014322.
The previous prime is 111144141014303. The next prime is 111144141014363. The reversal of 111144141014323 is 323410141441111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 111144141014323 - 29 = 111144141013811 is a prime.
It is a super-2 number, since 2×1111441410143232 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (111144141014303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55572070507161 + 55572070507162.
It is an arithmetic number, because the mean of its divisors is an integer number (55572070507162).
Almost surely, 2111144141014323 is an apocalyptic number.
111144141014323 is a deficient number, since it is larger than the sum of its proper divisors (1).
111144141014323 is an equidigital number, since it uses as much as digits as its factorization.
111144141014323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4608, while the sum is 31.
Adding to 111144141014323 its reverse (323410141441111), we get a palindrome (434554282455434).
The spelling of 111144141014323 in words is "one hundred eleven trillion, one hundred forty-four billion, one hundred forty-one million, fourteen thousand, three hundred twenty-three".
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