11114851152371 has 4 divisors (see below), whose sum is σ = 11114857876200. Its totient is φ = 11114844428544.

The previous prime is 11114851152343. The next prime is 11114851152401. The reversal of 11114851152371 is 17325115841111.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 11114851152371 - 2¹⁰ = 11114851151347 is a prime.

It is a super-3 number, since 3×11114851152371³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11114851152331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1031240 + ... + 4826298.

It is an arithmetic number, because the mean of its divisors is an integer number (2778714469050).

Almost surely, 2^{11114851152371} is an apocalyptic number.

11114851152371 is a deficient number, since it is larger than the sum of its proper divisors (6723829).

11114851152371 is an equidigital number, since it uses as much as digits as its factorization.

11114851152371 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6723828.

The product of its digits is 33600, while the sum is 41.

Adding to 11114851152371 its reverse (17325115841111), we get a palindrome (28439966993482).

The spelling of 11114851152371 in words is "eleven trillion, one hundred fourteen billion, eight hundred fifty-one million, one hundred fifty-two thousand, three hundred seventy-one".