1111550133601 has 4 divisors (see below), whose sum is σ = 1137400136752. Its totient is φ = 1085700130452.

The previous prime is 1111550133553. The next prime is 1111550133619. The reversal of 1111550133601 is 1063310551111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1111550133601 - 2²¹ = 1111548036449 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1111550133601.

It is not an unprimeable number, because it can be changed into a prime (1111550133671) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12925001511 + ... + 12925001596.

It is an arithmetic number, because the mean of its divisors is an integer number (284350034188).

Almost surely, 2^{1111550133601} is an apocalyptic number.

It is an amenable number.

1111550133601 is a deficient number, since it is larger than the sum of its proper divisors (25850003151).

1111550133601 is an equidigital number, since it uses as much as digits as its factorization.

1111550133601 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25850003150.

The product of its (nonzero) digits is 1350, while the sum is 28.

Adding to 1111550133601 its reverse (1063310551111), we get a palindrome (2174860684712).

The spelling of 1111550133601 in words is "one trillion, one hundred eleven billion, five hundred fifty million, one hundred thirty-three thousand, six hundred one".