Base | Representation |
---|---|
bin | 1010000111010001001110… |
… | …1110010000000110001011 |
3 | 1110101001200000010022201012 |
4 | 2201310103232100012023 |
5 | 2424142230303033003 |
6 | 35352242534114135 |
7 | 2225251665552443 |
oct | 241642356200613 |
9 | 43331600108635 |
10 | 11120001221003 |
11 | 35a7a69878424 |
12 | 12b7169aab94b |
13 | 6287c49480bc |
14 | 2a62d4b19123 |
15 | 1443cb8018d8 |
hex | a1d13b9018b |
11120001221003 has 2 divisors, whose sum is σ = 11120001221004. Its totient is φ = 11120001221002.
The previous prime is 11120001220987. The next prime is 11120001221107. The reversal of 11120001221003 is 30012210002111.
It is a weak prime.
It is an emirp because it is prime and its reverse (30012210002111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11120001221003 - 24 = 11120001220987 is a prime.
It is not a weakly prime, because it can be changed into another prime (11120001221603) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560000610501 + 5560000610502.
It is an arithmetic number, because the mean of its divisors is an integer number (5560000610502).
Almost surely, 211120001221003 is an apocalyptic number.
11120001221003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11120001221003 is an equidigital number, since it uses as much as digits as its factorization.
11120001221003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 11120001221003 its reverse (30012210002111), we get a palindrome (41132211223114).
The spelling of 11120001221003 in words is "eleven trillion, one hundred twenty billion, one million, two hundred twenty-one thousand, three".
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