Base | Representation |
---|---|
bin | 1010000111010001010100… |
… | …0110000100000000000011 |
3 | 1110101001201121102211000111 |
4 | 2201310111012010000003 |
5 | 2424142302201141011 |
6 | 35352245115332151 |
7 | 2225252365324552 |
oct | 241642506040003 |
9 | 43331647384014 |
10 | 11120024240131 |
11 | 35a7a8086aaa4 |
12 | 12b7175751057 |
13 | 6287c96477a1 |
14 | 2a62d7bcbd99 |
15 | 1443cd84c121 |
hex | a1d15184003 |
11120024240131 has 2 divisors, whose sum is σ = 11120024240132. Its totient is φ = 11120024240130.
The previous prime is 11120024240111. The next prime is 11120024240137. The reversal of 11120024240131 is 13104242002111.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11120024240131 is a prime.
It is a super-2 number, since 2×111200242401312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11120024240137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560012120065 + 5560012120066.
It is an arithmetic number, because the mean of its divisors is an integer number (5560012120066).
Almost surely, 211120024240131 is an apocalyptic number.
11120024240131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11120024240131 is an equidigital number, since it uses as much as digits as its factorization.
11120024240131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 11120024240131 its reverse (13104242002111), we get a palindrome (24224266242242).
The spelling of 11120024240131 in words is "eleven trillion, one hundred twenty billion, twenty-four million, two hundred forty thousand, one hundred thirty-one".
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