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11120034254057 is a prime number
BaseRepresentation
bin1010000111010001010110…
…1100010000110011101001
31110101001202022021120112122
42201310111230100303221
52424142312232112212
635352250114121025
72225252546412641
oct241642554206351
943331668246478
1011120034254057
1135a7a8648a673
1212b7178b80175
136287cb7427a1
142a62d9277521
151443ce679272
hexa1d15b10ce9

11120034254057 has 2 divisors, whose sum is σ = 11120034254058. Its totient is φ = 11120034254056.

The previous prime is 11120034254047. The next prime is 11120034254137. The reversal of 11120034254057 is 75045243002111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9290694148096 + 1829340105961 = 3048064^2 + 1352531^2 .

It is an emirp because it is prime and its reverse (75045243002111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11120034254057 - 210 = 11120034253033 is a prime.

It is a super-2 number, since 2×111200342540572 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11120034254047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560017127028 + 5560017127029.

It is an arithmetic number, because the mean of its divisors is an integer number (5560017127029).

Almost surely, 211120034254057 is an apocalyptic number.

It is an amenable number.

11120034254057 is a deficient number, since it is larger than the sum of its proper divisors (1).

11120034254057 is an equidigital number, since it uses as much as digits as its factorization.

11120034254057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 33600, while the sum is 35.

Adding to 11120034254057 its reverse (75045243002111), we get a palindrome (86165277256168).

The spelling of 11120034254057 in words is "eleven trillion, one hundred twenty billion, thirty-four million, two hundred fifty-four thousand, fifty-seven".