Base | Representation |
---|---|
bin | 1010000111010001101001… |
… | …0001110010101101101011 |
3 | 1110101001221200001220002021 |
4 | 2201310122101302231223 |
5 | 2424142441431414011 |
6 | 35352301503245311 |
7 | 2225254502432302 |
oct | 241643221625553 |
9 | 43331850056067 |
10 | 11120111201131 |
11 | 35a8015966099 |
12 | 12b719a8a9837 |
13 | 6288116743ba |
14 | 2a6305587439 |
15 | 1443d62c8471 |
hex | a1d1a472b6b |
11120111201131 has 2 divisors, whose sum is σ = 11120111201132. Its totient is φ = 11120111201130.
The previous prime is 11120111201119. The next prime is 11120111201137. The reversal of 11120111201131 is 13110211102111.
11120111201131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11120111201131 - 233 = 11111521266539 is a prime.
It is a super-2 number, since 2×111201112011312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11120111201137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560055600565 + 5560055600566.
It is an arithmetic number, because the mean of its divisors is an integer number (5560055600566).
Almost surely, 211120111201131 is an apocalyptic number.
11120111201131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11120111201131 is an equidigital number, since it uses as much as digits as its factorization.
11120111201131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 16.
Adding to 11120111201131 its reverse (13110211102111), we get a palindrome (24230322303242).
The spelling of 11120111201131 in words is "eleven trillion, one hundred twenty billion, one hundred eleven million, two hundred one thousand, one hundred thirty-one".
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