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1112012102017 is a prime number
BaseRepresentation
bin10000001011101001000…
…101100001100110000001
310221022022000221202221001
4100023221011201212001
5121204400044231032
62210503514332001
7143224460624065
oct20135105414601
93838260852831
101112012102017
11399668929033
1215b62272a001
1380b295b934b
143bb70955aa5
151ddd53123e7
hex102e9161981

1112012102017 has 2 divisors, whose sum is σ = 1112012102018. Its totient is φ = 1112012102016.

The previous prime is 1112012101973. The next prime is 1112012102059. The reversal of 1112012102017 is 7102012102111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1108354150656 + 3657951361 = 1052784^2 + 60481^2 .

It is a cyclic number.

It is not a de Polignac number, because 1112012102017 - 215 = 1112012069249 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1112012101985 and 1112012102003.

It is not a weakly prime, because it can be changed into another prime (1112012102077) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556006051008 + 556006051009.

It is an arithmetic number, because the mean of its divisors is an integer number (556006051009).

Almost surely, 21112012102017 is an apocalyptic number.

It is an amenable number.

1112012102017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1112012102017 is an equidigital number, since it uses as much as digits as its factorization.

1112012102017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 56, while the sum is 19.

Adding to 1112012102017 its reverse (7102012102111), we get a palindrome (8214024204128).

The spelling of 1112012102017 in words is "one trillion, one hundred twelve billion, twelve million, one hundred two thousand, seventeen".