Base | Representation |
---|---|
bin | 1010000111010001101011… |
… | …1111001100000001011001 |
3 | 1110101001222111110111000021 |
4 | 2201310122333030001121 |
5 | 2424143003003220043 |
6 | 35352303010310441 |
7 | 2225255005534504 |
oct | 241643277140131 |
9 | 43331874414007 |
10 | 11120123101273 |
11 | 35a802165391a |
12 | 12b71a2888421 |
13 | 628813c7cac4 |
14 | 2a6306da413b |
15 | 1443d73793ed |
hex | a1d1afcc059 |
11120123101273 has 2 divisors, whose sum is σ = 11120123101274. Its totient is φ = 11120123101272.
The previous prime is 11120123101259. The next prime is 11120123101331. The reversal of 11120123101273 is 37210132102111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9544688944704 + 1575434156569 = 3089448^2 + 1255163^2 .
It is a cyclic number.
It is not a de Polignac number, because 11120123101273 - 221 = 11120121004121 is a prime.
It is not a weakly prime, because it can be changed into another prime (11120123101223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560061550636 + 5560061550637.
It is an arithmetic number, because the mean of its divisors is an integer number (5560061550637).
Almost surely, 211120123101273 is an apocalyptic number.
It is an amenable number.
11120123101273 is a deficient number, since it is larger than the sum of its proper divisors (1).
11120123101273 is an equidigital number, since it uses as much as digits as its factorization.
11120123101273 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 504, while the sum is 25.
Adding to 11120123101273 its reverse (37210132102111), we get a palindrome (48330255203384).
The spelling of 11120123101273 in words is "eleven trillion, one hundred twenty billion, one hundred twenty-three million, one hundred one thousand, two hundred seventy-three".
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