11120133523 has 2 divisors, whose sum is σ = 11120133524. Its totient is φ = 11120133522.

The previous prime is 11120133511. The next prime is 11120133527. The reversal of 11120133523 is 32533102111.

It is a strong prime.

It is an emirp because it is prime and its reverse (32533102111) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11120133523 is a prime.

It is a super-3 number, since 3×11120133523³ (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11120133494 and 11120133503.

It is not a weakly prime, because it can be changed into another prime (11120133527) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560066761 + 5560066762.

It is an arithmetic number, because the mean of its divisors is an integer number (5560066762).

Almost surely, 2^11120133523 is an apocalyptic number.

11120133523 is a deficient number, since it is larger than the sum of its proper divisors (1).

11120133523 is an equidigital number, since it uses as much as digits as its factorization.

11120133523 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 11120133523 its reverse (32533102111), we get a palindrome (43653235634).

The spelling of 11120133523 in words is "eleven billion, one hundred twenty million, one hundred thirty-three thousand, five hundred twenty-three".