Base | Representation |
---|---|
bin | 110011110010000101… |
… | …0000101011011011011 |
3 | 101122000212020111100201 |
4 | 1213210022011123123 |
5 | 3310220210000243 |
6 | 123030245243031 |
7 | 11014455445645 |
oct | 1474412053333 |
9 | 348025214321 |
10 | 111202031323 |
11 | 43184714029 |
12 | 19675403477 |
13 | a642552b46 |
14 | 554cac1895 |
15 | 2d5c8d504d |
hex | 19e42856db |
111202031323 has 2 divisors, whose sum is σ = 111202031324. Its totient is φ = 111202031322.
The previous prime is 111202031251. The next prime is 111202031333. The reversal of 111202031323 is 323130202111.
It is a strong prime.
It is an emirp because it is prime and its reverse (323130202111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 111202031323 - 213 = 111202023131 is a prime.
It is a super-2 number, since 2×1112020313232 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 111202031323.
It is not a weakly prime, because it can be changed into another prime (111202031333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55601015661 + 55601015662.
It is an arithmetic number, because the mean of its divisors is an integer number (55601015662).
Almost surely, 2111202031323 is an apocalyptic number.
111202031323 is a deficient number, since it is larger than the sum of its proper divisors (1).
111202031323 is an equidigital number, since it uses as much as digits as its factorization.
111202031323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 111202031323 its reverse (323130202111), we get a palindrome (434332233434).
The spelling of 111202031323 in words is "one hundred eleven billion, two hundred two million, thirty-one thousand, three hundred twenty-three".
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