Base | Representation |
---|---|
bin | 10000001011101001101… |
… | …011110101101001110011 |
3 | 10221022022201212001012111 |
4 | 100023221223311221303 |
5 | 121204410132130101 |
6 | 2210504513510151 |
7 | 143224642164604 |
oct | 20135153655163 |
9 | 3838281761174 |
10 | 1112022145651 |
11 | 399673568a5a |
12 | 15b625b72357 |
13 | 80b2b6c4a21 |
14 | 3bb7200bdab |
15 | 1ddd6148251 |
hex | 102e9af5a73 |
1112022145651 has 2 divisors, whose sum is σ = 1112022145652. Its totient is φ = 1112022145650.
The previous prime is 1112022145573. The next prime is 1112022145679. The reversal of 1112022145651 is 1565412202111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1112022145651 - 237 = 974583192179 is a prime.
It is not a weakly prime, because it can be changed into another prime (1112022140651) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556011072825 + 556011072826.
It is an arithmetic number, because the mean of its divisors is an integer number (556011072826).
Almost surely, 21112022145651 is an apocalyptic number.
1112022145651 is a deficient number, since it is larger than the sum of its proper divisors (1).
1112022145651 is an equidigital number, since it uses as much as digits as its factorization.
1112022145651 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4800, while the sum is 31.
Adding to 1112022145651 its reverse (1565412202111), we get a palindrome (2677434347762).
The spelling of 1112022145651 in words is "one trillion, one hundred twelve billion, twenty-two million, one hundred forty-five thousand, six hundred fifty-one".
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