11120433203131 has 8 divisors (see below), whose sum is σ = 12714413220320. Its totient is φ = 9527789861568.

The previous prime is 11120433203069. The next prime is 11120433203161. The reversal of 11120433203131 is 13130233402111.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11120433203131 - 2¹¹ = 11120433201083 is a prime.

It is a super-2 number, since 2×11120433203131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11120433203096 and 11120433203105.

It is not an unprimeable number, because it can be changed into a prime (11120433203161) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 334151076 + ... + 334184353.

It is an arithmetic number, because the mean of its divisors is an integer number (1589301652540).

Almost surely, 2^{11120433203131} is an apocalyptic number.

11120433203131 is a deficient number, since it is larger than the sum of its proper divisors (1593980017189).

11120433203131 is an equidigital number, since it uses as much as digits as its factorization.

11120433203131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 668337813.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 11120433203131 its reverse (13130233402111), we get a palindrome (24250666605242).

The spelling of 11120433203131 in words is "eleven trillion, one hundred twenty billion, four hundred thirty-three million, two hundred three thousand, one hundred thirty-one".