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1112111000083 is a prime number
BaseRepresentation
bin10000001011101110111…
…110110010101000010011
310221022112221001022120101
4100023232332302220103
5121210100404000313
62210521410153231
7143230101346456
oct20135676625023
93838487038511
101112111000083
11399709737676
1215b64b882817
1380b43c35405
143bb7db3b49d
151ddddd4a5dd
hex102eefb2a13

1112111000083 has 2 divisors, whose sum is σ = 1112111000084. Its totient is φ = 1112111000082.

The previous prime is 1112111000069. The next prime is 1112111000093. The reversal of 1112111000083 is 3800001112111.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1112111000083 - 25 = 1112111000051 is a prime.

It is a super-2 number, since 2×11121110000832 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1112111000083.

It is not a weakly prime, because it can be changed into another prime (1112111000003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556055500041 + 556055500042.

It is an arithmetic number, because the mean of its divisors is an integer number (556055500042).

Almost surely, 21112111000083 is an apocalyptic number.

1112111000083 is a deficient number, since it is larger than the sum of its proper divisors (1).

1112111000083 is an equidigital number, since it uses as much as digits as its factorization.

1112111000083 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 19.

Adding to 1112111000083 its reverse (3800001112111), we get a palindrome (4912112112194).

The spelling of 1112111000083 in words is "one trillion, one hundred twelve billion, one hundred eleven million, eighty-three", and thus it is an aban number.