Base | Representation |
---|---|
bin | 10000001011101110111… |
… | …110110010101000010011 |
3 | 10221022112221001022120101 |
4 | 100023232332302220103 |
5 | 121210100404000313 |
6 | 2210521410153231 |
7 | 143230101346456 |
oct | 20135676625023 |
9 | 3838487038511 |
10 | 1112111000083 |
11 | 399709737676 |
12 | 15b64b882817 |
13 | 80b43c35405 |
14 | 3bb7db3b49d |
15 | 1ddddd4a5dd |
hex | 102eefb2a13 |
1112111000083 has 2 divisors, whose sum is σ = 1112111000084. Its totient is φ = 1112111000082.
The previous prime is 1112111000069. The next prime is 1112111000093. The reversal of 1112111000083 is 3800001112111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1112111000083 - 25 = 1112111000051 is a prime.
It is a super-2 number, since 2×11121110000832 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1112111000083.
It is not a weakly prime, because it can be changed into another prime (1112111000003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556055500041 + 556055500042.
It is an arithmetic number, because the mean of its divisors is an integer number (556055500042).
Almost surely, 21112111000083 is an apocalyptic number.
1112111000083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1112111000083 is an equidigital number, since it uses as much as digits as its factorization.
1112111000083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 19.
Adding to 1112111000083 its reverse (3800001112111), we get a palindrome (4912112112194).
The spelling of 1112111000083 in words is "one trillion, one hundred twelve billion, one hundred eleven million, eighty-three", and thus it is an aban number.
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