Base | Representation |
---|---|
bin | 11001010010010111001100… |
… | …000010001010000110111011 |
3 | 112120202212012222100002012002 |
4 | 121102113030002022012323 |
5 | 104034103221344004313 |
6 | 1032310315130011215 |
7 | 32265606044536151 |
oct | 3122271402120673 |
9 | 476685188302162 |
10 | 111213011313083 |
11 | 3248819a629399 |
12 | 105819b0576b0b |
13 | 4a0945a3bc294 |
14 | 1d66a4a4db3d1 |
15 | cccd8b837058 |
hex | 6525cc08a1bb |
111213011313083 has 2 divisors, whose sum is σ = 111213011313084. Its totient is φ = 111213011313082.
The previous prime is 111213011313071. The next prime is 111213011313143. The reversal of 111213011313083 is 380313110312111.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111213011313083 is a prime.
It is not a weakly prime, because it can be changed into another prime (111213011313883) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55606505656541 + 55606505656542.
It is an arithmetic number, because the mean of its divisors is an integer number (55606505656542).
Almost surely, 2111213011313083 is an apocalyptic number.
111213011313083 is a deficient number, since it is larger than the sum of its proper divisors (1).
111213011313083 is an equidigital number, since it uses as much as digits as its factorization.
111213011313083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 29.
Adding to 111213011313083 its reverse (380313110312111), we get a palindrome (491526121625194).
The spelling of 111213011313083 in words is "one hundred eleven trillion, two hundred thirteen billion, eleven million, three hundred thirteen thousand, eighty-three".
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