Base | Representation |
---|---|
bin | 110011110010011100… |
… | …0001011000110111011 |
3 | 101122001200222022121001 |
4 | 1213210320023012323 |
5 | 3310231303110321 |
6 | 123031400225431 |
7 | 11014663236055 |
oct | 1474470130673 |
9 | 348050868531 |
10 | 111214113211 |
11 | 43190516363 |
12 | 1967946b277 |
13 | a644bc31a6 |
14 | 55505488d5 |
15 | 2d5d9bec91 |
hex | 19e4e0b1bb |
111214113211 has 2 divisors, whose sum is σ = 111214113212. Its totient is φ = 111214113210.
The previous prime is 111214113187. The next prime is 111214113259. The reversal of 111214113211 is 112311412111.
It is a m-pointer prime, because the next prime (111214113259) can be obtained adding 111214113211 to its product of digits (48).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 111214113211 - 213 = 111214105019 is a prime.
It is not a weakly prime, because it can be changed into another prime (111214113281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55607056605 + 55607056606.
It is an arithmetic number, because the mean of its divisors is an integer number (55607056606).
Almost surely, 2111214113211 is an apocalyptic number.
111214113211 is a deficient number, since it is larger than the sum of its proper divisors (1).
111214113211 is an equidigital number, since it uses as much as digits as its factorization.
111214113211 is an evil number, because the sum of its binary digits is even.
The product of its digits is 48, while the sum is 19.
Adding to 111214113211 its reverse (112311412111), we get a palindrome (223525525322).
The spelling of 111214113211 in words is "one hundred eleven billion, two hundred fourteen million, one hundred thirteen thousand, two hundred eleven".
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