Base | Representation |
---|---|
bin | 1010000111010111001110… |
… | …1011011111101011011011 |
3 | 1110101012211012102012210111 |
4 | 2201311303223133223123 |
5 | 2424204024421024011 |
6 | 35353110403425151 |
7 | 2225336614443613 |
oct | 241656353375333 |
9 | 43335735365714 |
10 | 11121611111131 |
11 | 35a8715594734 |
12 | 12b75390851b7 |
13 | 6289c0334701 |
14 | 2a6408865a43 |
15 | 144472d06121 |
hex | a1d73adfadb |
11121611111131 has 2 divisors, whose sum is σ = 11121611111132. Its totient is φ = 11121611111130.
The previous prime is 11121611111059. The next prime is 11121611111167. The reversal of 11121611111131 is 13111111612111.
It is a m-pointer prime, because the next prime (11121611111167) can be obtained adding 11121611111131 to its product of digits (36).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11121611111131 - 219 = 11121610586843 is a prime.
It is a super-2 number, since 2×111216111111312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11121611117131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560805555565 + 5560805555566.
It is an arithmetic number, because the mean of its divisors is an integer number (5560805555566).
Almost surely, 211121611111131 is an apocalyptic number.
11121611111131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11121611111131 is an equidigital number, since it uses as much as digits as its factorization.
11121611111131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 36, while the sum is 22.
Adding to 11121611111131 its reverse (13111111612111), we get a palindrome (24232722723242).
The spelling of 11121611111131 in words is "eleven trillion, one hundred twenty-one billion, six hundred eleven million, one hundred eleven thousand, one hundred thirty-one".
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