Base | Representation |
---|---|
bin | 1010000111011000101110… |
… | …1001000000111001111011 |
3 | 1110101020212012212002000212 |
4 | 2201312023221000321323 |
5 | 2424210340324121404 |
6 | 35353214324021335 |
7 | 2225352565426565 |
oct | 241661351007173 |
9 | 43336765762025 |
10 | 11122013113979 |
11 | 35a89014a8399 |
12 | 12b762b83184b |
13 | 628a556c7811 |
14 | 2a6445dcc335 |
15 | 14449826306e |
hex | a1d8ba40e7b |
11122013113979 has 2 divisors, whose sum is σ = 11122013113980. Its totient is φ = 11122013113978.
The previous prime is 11122013113963. The next prime is 11122013114053. The reversal of 11122013113979 is 97931131022111.
11122013113979 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11122013113979 - 24 = 11122013113963 is a prime.
It is not a weakly prime, because it can be changed into another prime (11122013113909) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5561006556989 + 5561006556990.
It is an arithmetic number, because the mean of its divisors is an integer number (5561006556990).
Almost surely, 211122013113979 is an apocalyptic number.
11122013113979 is a deficient number, since it is larger than the sum of its proper divisors (1).
11122013113979 is an equidigital number, since it uses as much as digits as its factorization.
11122013113979 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20412, while the sum is 41.
The spelling of 11122013113979 in words is "eleven trillion, one hundred twenty-two billion, thirteen million, one hundred thirteen thousand, nine hundred seventy-nine".
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