Base | Representation |
---|---|
bin | 1010000111011001001000… |
… | …0001001101011011000011 |
3 | 1110101021010200012112200221 |
4 | 2201312102001031123003 |
5 | 2424211100222320003 |
6 | 35353233105323511 |
7 | 2225355335111524 |
oct | 241662201153303 |
9 | 43337120175627 |
10 | 11122120120003 |
11 | 35a8956944622 |
12 | 12b765b636597 |
13 | 628a719221a9 |
14 | 2a64562c484b |
15 | 1444a284d7bd |
hex | a1d9204d6c3 |
11122120120003 has 2 divisors, whose sum is σ = 11122120120004. Its totient is φ = 11122120120002.
The previous prime is 11122120119991. The next prime is 11122120120087. The reversal of 11122120120003 is 30002102122111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11122120120003 - 29 = 11122120119491 is a prime.
It is not a weakly prime, because it can be changed into another prime (11122120123003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5561060060001 + 5561060060002.
It is an arithmetic number, because the mean of its divisors is an integer number (5561060060002).
Almost surely, 211122120120003 is an apocalyptic number.
11122120120003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11122120120003 is an equidigital number, since it uses as much as digits as its factorization.
11122120120003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 11122120120003 its reverse (30002102122111), we get a palindrome (41124222242114).
The spelling of 11122120120003 in words is "eleven trillion, one hundred twenty-two billion, one hundred twenty million, one hundred twenty thousand, three".
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