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11122122010033 is a prime number
BaseRepresentation
bin1010000111011001001000…
…1000011010110110110001
31110101021010210202120100001
42201312102020122312301
52424211101213310113
635353233214030001
72225355360143026
oct241662210326661
943337123676301
1011122122010033
1135a8957a15631
1212b76601a8301
13628a72134558
142a645665754d
151444a2ac37dd
hexa1d9221adb1

11122122010033 has 2 divisors, whose sum is σ = 11122122010034. Its totient is φ = 11122122010032.

The previous prime is 11122122010007. The next prime is 11122122010127. The reversal of 11122122010033 is 33001022122111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10984074093729 + 138047916304 = 3314223^2 + 371548^2 .

It is a cyclic number.

It is not a de Polignac number, because 11122122010033 - 217 = 11122121878961 is a prime.

It is a super-2 number, since 2×111221220100332 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11122122010133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5561061005016 + 5561061005017.

It is an arithmetic number, because the mean of its divisors is an integer number (5561061005017).

Almost surely, 211122122010033 is an apocalyptic number.

It is an amenable number.

11122122010033 is a deficient number, since it is larger than the sum of its proper divisors (1).

11122122010033 is an equidigital number, since it uses as much as digits as its factorization.

11122122010033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 11122122010033 its reverse (33001022122111), we get a palindrome (44123144132144).

The spelling of 11122122010033 in words is "eleven trillion, one hundred twenty-two billion, one hundred twenty-two million, ten thousand, thirty-three".