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11122201313233 is a prime number
BaseRepresentation
bin1010000111011001011011…
…0110111011111111010001
31110101021100022222120212121
42201312112312323333101
52424211232014010413
635353245125454241
72225360342204503
oct241662666737721
943337308876777
1011122201313233
1135a899876026a
1212b7682871381
13628a856ac71a
142a6462dbbd73
151444a9a3ab8d
hexa1d96dbbfd1

11122201313233 has 2 divisors, whose sum is σ = 11122201313234. Its totient is φ = 11122201313232.

The previous prime is 11122201313221. The next prime is 11122201313239. The reversal of 11122201313233 is 33231310222111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10870525514304 + 251675798929 = 3297048^2 + 501673^2 .

It is a cyclic number.

It is not a de Polignac number, because 11122201313233 - 217 = 11122201182161 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11122201313198 and 11122201313207.

It is not a weakly prime, because it can be changed into another prime (11122201313239) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5561100656616 + 5561100656617.

It is an arithmetic number, because the mean of its divisors is an integer number (5561100656617).

Almost surely, 211122201313233 is an apocalyptic number.

It is an amenable number.

11122201313233 is a deficient number, since it is larger than the sum of its proper divisors (1).

11122201313233 is an equidigital number, since it uses as much as digits as its factorization.

11122201313233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 11122201313233 its reverse (33231310222111), we get a palindrome (44353511535344).

The spelling of 11122201313233 in words is "eleven trillion, one hundred twenty-two billion, two hundred one million, three hundred thirteen thousand, two hundred thirty-three".