Search a number
-
+
11122443331 = 39821279311
BaseRepresentation
bin10100101101111001…
…10000010001000011
31001201010211122220121
422112330300101003
5140234321141311
65035400321111
7542424131326
oct122674602103
931633748817
1011122443331
11479836932a
1221a4a73197
1310833c871c
147772647bd
154516c8b71
hex296f30443

11122443331 has 4 divisors (see below), whose sum is σ = 11122762464. Its totient is φ = 11122124200.

The previous prime is 11122443281. The next prime is 11122443373. The reversal of 11122443331 is 13334422111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11122443331 - 229 = 10585572419 is a prime.

It is a super-2 number, since 2×111224433312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11122443296 and 11122443305.

It is not an unprimeable number, because it can be changed into a prime (11122443391) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 99835 + ... + 179476.

It is an arithmetic number, because the mean of its divisors is an integer number (2780690616).

Almost surely, 211122443331 is an apocalyptic number.

11122443331 is a deficient number, since it is larger than the sum of its proper divisors (319133).

11122443331 is an equidigital number, since it uses as much as digits as its factorization.

11122443331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 319132.

The product of its digits is 1728, while the sum is 25.

Adding to 11122443331 its reverse (13334422111), we get a palindrome (24456865442).

The spelling of 11122443331 in words is "eleven billion, one hundred twenty-two million, four hundred forty-three thousand, three hundred thirty-one".

Divisors: 1 39821 279311 11122443331