Base | Representation |
---|---|
bin | 1010000111011011000101… |
… | …0100101010011000111011 |
3 | 1110101022111021110010011111 |
4 | 2201312301110222120323 |
5 | 2424213134200004313 |
6 | 35353401150141151 |
7 | 2225404343143633 |
oct | 241666124523073 |
9 | 43338437403144 |
10 | 11122645313083 |
11 | 35a90a6348997 |
12 | 12b77874b17b7 |
13 | 628b26688325 |
14 | 2a64a5d576c3 |
15 | 1444d39e143d |
hex | a1db152a63b |
11122645313083 has 2 divisors, whose sum is σ = 11122645313084. Its totient is φ = 11122645313082.
The previous prime is 11122645313033. The next prime is 11122645313099. The reversal of 11122645313083 is 38031354622111.
11122645313083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11122645313083 - 213 = 11122645304891 is a prime.
It is not a weakly prime, because it can be changed into another prime (11122645313033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5561322656541 + 5561322656542.
It is an arithmetic number, because the mean of its divisors is an integer number (5561322656542).
Almost surely, 211122645313083 is an apocalyptic number.
11122645313083 is a deficient number, since it is larger than the sum of its proper divisors (1).
11122645313083 is an equidigital number, since it uses as much as digits as its factorization.
11122645313083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 103680, while the sum is 40.
Adding to 11122645313083 its reverse (38031354622111), we get a palindrome (49153999935194).
The spelling of 11122645313083 in words is "eleven trillion, one hundred twenty-two billion, six hundred forty-five million, three hundred thirteen thousand, eighty-three".
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