Base | Representation |
---|---|
bin | 110011110010111110… |
… | …1101110000001000011 |
3 | 101122002222021112201022 |
4 | 1213211331232001003 |
5 | 3310300440003011 |
6 | 123033251100055 |
7 | 11015304216326 |
oct | 1474575560103 |
9 | 348088245638 |
10 | 111232344131 |
11 | 4319a838537 |
12 | 196835a162b |
13 | a64890730c |
14 | 5552b327bd |
15 | 2d603c18db |
hex | 19e5f6e043 |
111232344131 has 2 divisors, whose sum is σ = 111232344132. Its totient is φ = 111232344130.
The previous prime is 111232344107. The next prime is 111232344149. The reversal of 111232344131 is 131443232111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111232344131 - 210 = 111232343107 is a prime.
It is a super-2 number, since 2×1112323441312 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 111232344131.
It is not a weakly prime, because it can be changed into another prime (111232344161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55616172065 + 55616172066.
It is an arithmetic number, because the mean of its divisors is an integer number (55616172066).
Almost surely, 2111232344131 is an apocalyptic number.
111232344131 is a deficient number, since it is larger than the sum of its proper divisors (1).
111232344131 is an equidigital number, since it uses as much as digits as its factorization.
111232344131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1728, while the sum is 26.
Adding to 111232344131 its reverse (131443232111), we get a palindrome (242675576242).
The spelling of 111232344131 in words is "one hundred eleven billion, two hundred thirty-two million, three hundred forty-four thousand, one hundred thirty-one".
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