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1112420443131 = 33103400007351
BaseRepresentation
bin10000001100000001011…
…011001110001111111011
310221100100111022122122000
4100030001123032033323
5121211214113140011
62211012222432043
7143240546516004
oct20140133161773
93840314278560
101112420443131
11399858380828
1215b717432623
1380b9308b3ca
143bbacc8c1ab
151de0b0c2356
hex103016ce3fb

1112420443131 has 16 divisors (see below), whose sum is σ = 1664030584320. Its totient is φ = 734413494600.

The previous prime is 1112420443091. The next prime is 1112420443157. The reversal of 1112420443131 is 1313440242111.

It is a happy number.

1112420443131 is a `hidden beast` number, since 1 + 1 + 1 + 24 + 204 + 431 + 3 + 1 = 666.

It is not a de Polignac number, because 1112420443131 - 221 = 1112418345979 is a prime.

It is a super-2 number, since 2×11124204431312 (a number of 25 digits) contains 22 as substring.

It is a hoax number, since the sum of its digits (27) coincides with the sum of the digits of its distinct prime factors.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 1112420443095 and 1112420443104.

It is not an unprimeable number, because it can be changed into a prime (1112420443181) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 200000895 + ... + 200006456.

It is an arithmetic number, because the mean of its divisors is an integer number (104001911520).

Almost surely, 21112420443131 is an apocalyptic number.

1112420443131 is a deficient number, since it is larger than the sum of its proper divisors (551610141189).

1112420443131 is a wasteful number, since it uses less digits than its factorization.

1112420443131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 400007463 (or 400007457 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 27.

Adding to 1112420443131 its reverse (1313440242111), we get a palindrome (2425860685242).

It can be divided in two parts, 1112420 and 443131, that added together give a palindrome (1555551).

The spelling of 1112420443131 in words is "one trillion, one hundred twelve billion, four hundred twenty million, four hundred forty-three thousand, one hundred thirty-one".

Divisors: 1 3 9 27 103 309 927 2781 400007351 1200022053 3600066159 10800198477 41200757153 123602271459 370806814377 1112420443131