Base | Representation |
---|---|
bin | 110011110011010011… |
… | …0011000011000101001 |
3 | 101122010201100002112021 |
4 | 1213212212120120221 |
5 | 3310311202102213 |
6 | 123034311344441 |
7 | 11015463633112 |
oct | 1474646303051 |
9 | 348121302467 |
10 | 111243003433 |
11 | 431a5858a81 |
12 | 19687082121 |
13 | a64ab99cb3 |
14 | 5554309209 |
15 | 2d612c9d8d |
hex | 19e6998629 |
111243003433 has 4 divisors (see below), whose sum is σ = 111253507668. Its totient is φ = 111232499200.
The previous prime is 111243003401. The next prime is 111243003451. The reversal of 111243003433 is 334300342111.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 90406658329 + 20836345104 = 300677^2 + 144348^2 .
It is a cyclic number.
It is not a de Polignac number, because 111243003433 - 25 = 111243003401 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 111243003398 and 111243003407.
It is not an unprimeable number, because it can be changed into a prime (111243003463) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5236216 + ... + 5257417.
It is an arithmetic number, because the mean of its divisors is an integer number (27813376917).
Almost surely, 2111243003433 is an apocalyptic number.
It is an amenable number.
111243003433 is a deficient number, since it is larger than the sum of its proper divisors (10504235).
111243003433 is a wasteful number, since it uses less digits than its factorization.
111243003433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10504234.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 111243003433 its reverse (334300342111), we get a palindrome (445543345544).
The spelling of 111243003433 in words is "one hundred eleven billion, two hundred forty-three million, three thousand, four hundred thirty-three".
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