111243031311433 has 16 divisors (see below), whose sum is σ = 127365376665600. Its totient is φ = 95178312904896.

The previous prime is 111243031311389. The next prime is 111243031311437. The reversal of 111243031311433 is 334113130342111.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-111243031311433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 111243031311395 and 111243031311404.

It is not an unprimeable number, because it can be changed into a prime (111243031311437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 255553035 + ... + 255987967.

It is an arithmetic number, because the mean of its divisors is an integer number (7960336041600).

Almost surely, 2^{111243031311433} is an apocalyptic number.

It is an amenable number.

111243031311433 is a deficient number, since it is larger than the sum of its proper divisors (16122345354167).

111243031311433 is an equidigital number, since it uses as much as digits as its factorization.

111243031311433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 501096.

The product of its (nonzero) digits is 7776, while the sum is 31.

Adding to 111243031311433 its reverse (334113130342111), we get a palindrome (445356161653544).

The spelling of 111243031311433 in words is "one hundred eleven trillion, two hundred forty-three billion, thirty-one million, three hundred eleven thousand, four hundred thirty-three".