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11125662624113 is a prime number
BaseRepresentation
bin1010000111100110010100…
…1010110010100101110001
31110101121021120001101202212
42201321211022302211301
52424240324112432423
635355020413421505
72225542201646042
oct241714512624561
943347246041685
1011125662624113
1135aa404562374
1212b8289a9a895
136291b782107b
142a66b09888c9
1514460d854578
hexa1e652b2971

11125662624113 has 2 divisors, whose sum is σ = 11125662624114. Its totient is φ = 11125662624112.

The previous prime is 11125662624067. The next prime is 11125662624121. The reversal of 11125662624113 is 31142626652111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10479677496289 + 645985127824 = 3237233^2 + 803732^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11125662624113 is a prime.

It is not a weakly prime, because it can be changed into another prime (11125662627113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5562831312056 + 5562831312057.

It is an arithmetic number, because the mean of its divisors is an integer number (5562831312057).

Almost surely, 211125662624113 is an apocalyptic number.

It is an amenable number.

11125662624113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11125662624113 is an equidigital number, since it uses as much as digits as its factorization.

11125662624113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 103680, while the sum is 41.

The spelling of 11125662624113 in words is "eleven trillion, one hundred twenty-five billion, six hundred sixty-two million, six hundred twenty-four thousand, one hundred thirteen".