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1113000123331 = 532499794041
BaseRepresentation
bin10000001100100011111…
…110100001101111000011
310221101211220002110101001
4100030203332201233003
5121213411012421311
62211145531152431
7143261115644515
oct20144376415703
93841756073331
101113000123331
1139a025610078
1215b8595a5717
1380c561c1145
143bc25c65bb5
151de41e294c1
hex10323fa1bc3

1113000123331 has 12 divisors (see below), whose sum is σ = 1136671123000. Its totient is φ = 1089810371520.

The previous prime is 1113000123317. The next prime is 1113000123337. The reversal of 1113000123331 is 1333210003111.

It is not a de Polignac number, because 1113000123331 - 225 = 1112966568899 is a prime.

It is a super-2 number, since 2×11130001233312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1113000123299 and 1113000123308.

It is not an unprimeable number, because it can be changed into a prime (1113000123337) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1004671 + ... + 1798711.

Almost surely, 21113000123331 is an apocalyptic number.

1113000123331 is a deficient number, since it is larger than the sum of its proper divisors (23670999669).

1113000123331 is an frugal number, since it uses more digits than its factorization.

1113000123331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 794646 (or 794593 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1113000123331 its reverse (1333210003111), we get a palindrome (2446210126442).

The spelling of 1113000123331 in words is "one trillion, one hundred thirteen billion, one hundred twenty-three thousand, three hundred thirty-one".

Divisors: 1 53 499 2809 26447 794041 1401691 42084173 396226459 2230461169 21000002327 1113000123331