Base | Representation |
---|---|
bin | 10100101110110011… |
… | …01000000001100111 |
3 | 1001201200002011211110 |
4 | 22113121220001213 |
5 | 140243240334001 |
6 | 5040230440103 |
7 | 542545352565 |
oct | 122731500147 |
9 | 31650064743 |
10 | 11130011751 |
11 | 47a1668621 |
12 | 21a7503033 |
13 | 1084b48591 |
14 | 778274a35 |
15 | 4521c13d6 |
hex | 297668067 |
11130011751 has 16 divisors (see below), whose sum is σ = 14881104000. Its totient is φ = 7399495008.
The previous prime is 11130011743. The next prime is 11130011771. The reversal of 11130011751 is 15711003111.
It is not a de Polignac number, because 11130011751 - 23 = 11130011743 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11130011701) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1763800 + ... + 1770098.
It is an arithmetic number, because the mean of its divisors is an integer number (930069000).
Almost surely, 211130011751 is an apocalyptic number.
11130011751 is a deficient number, since it is larger than the sum of its proper divisors (3751092249).
11130011751 is an equidigital number, since it uses as much as digits as its factorization.
11130011751 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7838.
The product of its (nonzero) digits is 105, while the sum is 21.
Adding to 11130011751 its reverse (15711003111), we get a palindrome (26841014862).
The spelling of 11130011751 in words is "eleven billion, one hundred thirty million, eleven thousand, seven hundred fifty-one".
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