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111300301113 = 3161983229037
BaseRepresentation
bin110011110101000000…
…0111101000100111001
3101122021201011010011120
41213222000331010321
53310420334113423
6123044115415453
711020060643541
oct1475200750471
9348251133146
10111300301113
1143225133631
12196a22b4589
13a659a0bc51
14555bb82321
152d66346ee3
hex19ea03d139

111300301113 has 8 divisors (see below), whose sum is σ = 148401965568. Its totient is φ = 74199418704.

The previous prime is 111300301069. The next prime is 111300301157. The reversal of 111300301113 is 311103003111.

It is an interprime number because it is at equal distance from previous prime (111300301069) and next prime (111300301157).

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 111300301113 - 222 = 111296106809 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 111300301092 and 111300301101.

It is not an unprimeable number, because it can be changed into a prime (111300301193) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 371431 + ... + 600467.

It is an arithmetic number, because the mean of its divisors is an integer number (18550245696).

Almost surely, 2111300301113 is an apocalyptic number.

It is an amenable number.

111300301113 is a deficient number, since it is larger than the sum of its proper divisors (37101664455).

111300301113 is a wasteful number, since it uses less digits than its factorization.

111300301113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 391023.

The product of its (nonzero) digits is 27, while the sum is 15.

Adding to 111300301113 its reverse (311103003111), we get a palindrome (422403304224).

The spelling of 111300301113 in words is "one hundred eleven billion, three hundred million, three hundred one thousand, one hundred thirteen".

Divisors: 1 3 161983 229037 485949 687111 37100100371 111300301113