Base | Representation |
---|---|
bin | 1010000111110110100110… |
… | …0011100101011101110001 |
3 | 1110102000120000022001102222 |
4 | 2201331221203211131301 |
5 | 2424323300441400423 |
6 | 35401022111250425 |
7 | 2226055356145160 |
oct | 241755143453561 |
9 | 43360500261388 |
10 | 11130031200113 |
11 | 36012464a9161 |
12 | 12b90a8b19a15 |
13 | 629732900b97 |
14 | 2a69a6c433d7 |
15 | 1447b71323c8 |
hex | a1f698e5771 |
11130031200113 has 16 divisors (see below), whose sum is σ = 12789552804480. Its totient is φ = 9487916798976.
The previous prime is 11130031200107. The next prime is 11130031200157. The reversal of 11130031200113 is 31100213003111.
It is not a de Polignac number, because 11130031200113 - 214 = 11130031183729 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11130031200091 and 11130031200100.
It is not an unprimeable number, because it can be changed into a prime (11130031209113) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3630683 + ... + 5953311.
It is an arithmetic number, because the mean of its divisors is an integer number (799347050280).
Almost surely, 211130031200113 is an apocalyptic number.
It is an amenable number.
11130031200113 is a deficient number, since it is larger than the sum of its proper divisors (1659521604367).
11130031200113 is a wasteful number, since it uses less digits than its factorization.
11130031200113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2326376.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 11130031200113 its reverse (31100213003111), we get a palindrome (42230244203224).
The spelling of 11130031200113 in words is "eleven trillion, one hundred thirty billion, thirty-one million, two hundred thousand, one hundred thirteen".
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