11130040301001 has 4 divisors (see below), whose sum is σ = 14840053734672. Its totient is φ = 7420026867332.

The previous prime is 11130040300961. The next prime is 11130040301011. The reversal of 11130040301001 is 10010304003111.

11130040301001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11130040301001 - 2¹⁰ = 11130040299977 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11130040301011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1855006716831 + ... + 1855006716836.

It is an arithmetic number, because the mean of its divisors is an integer number (3710013433668).

Almost surely, 2^{11130040301001} is an apocalyptic number.

It is an amenable number.

11130040301001 is a deficient number, since it is larger than the sum of its proper divisors (3710013433671).

11130040301001 is an equidigital number, since it uses as much as digits as its factorization.

11130040301001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3710013433670.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 11130040301001 its reverse (10010304003111), we get a palindrome (21140344304112).

The spelling of 11130040301001 in words is "eleven trillion, one hundred thirty billion, forty million, three hundred one thousand, one".