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11130073657 is a prime number
BaseRepresentation
bin10100101110110011…
…10111001000111001
31001201200012022202021
422113121313020321
5140243244324112
65040232034441
7542546031223
oct122731671071
931650168667
1011130073657
1147a170008a
1221a7532a21
131084b6a801
1477828d413
154521d4907
hex297677239

11130073657 has 2 divisors, whose sum is σ = 11130073658. Its totient is φ = 11130073656.

The previous prime is 11130073639. The next prime is 11130073663. The reversal of 11130073657 is 75637003111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8291741481 + 2838332176 = 91059^2 + 53276^2 .

It is an emirp because it is prime and its reverse (75637003111) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11130073657 is a prime.

It is a super-2 number, since 2×111300736572 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11130073607) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565036828 + 5565036829.

It is an arithmetic number, because the mean of its divisors is an integer number (5565036829).

Almost surely, 211130073657 is an apocalyptic number.

It is an amenable number.

11130073657 is a deficient number, since it is larger than the sum of its proper divisors (1).

11130073657 is an equidigital number, since it uses as much as digits as its factorization.

11130073657 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13230, while the sum is 34.

Adding to 11130073657 its reverse (75637003111), we get a palindrome (86767076768).

The spelling of 11130073657 in words is "eleven billion, one hundred thirty million, seventy-three thousand, six hundred fifty-seven".