111301243321 has 2 divisors, whose sum is σ = 111301243322. Its totient is φ = 111301243320.

The previous prime is 111301243289. The next prime is 111301243349. The reversal of 111301243321 is 123342103111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 89592462400 + 21708780921 = 299320^2 + 147339^2 .

It is a cyclic number.

It is not a de Polignac number, because 111301243321 - 2⁵ = 111301243289 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 111301243292 and 111301243301.

It is not a weakly prime, because it can be changed into another prime (111301243621) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55650621660 + 55650621661.

It is an arithmetic number, because the mean of its divisors is an integer number (55650621661).

Almost surely, 2^111301243321 is an apocalyptic number.

It is an amenable number.

111301243321 is a deficient number, since it is larger than the sum of its proper divisors (1).

111301243321 is an equidigital number, since it uses as much as digits as its factorization.

111301243321 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 111301243321 its reverse (123342103111), we get a palindrome (234643346432).

The spelling of 111301243321 in words is "one hundred eleven billion, three hundred one million, two hundred forty-three thousand, three hundred twenty-one".