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11130200313 = 33710066771
BaseRepresentation
bin10100101110110100…
…10110000011111001
31001201200102202111020
422113122112003321
5140243312402223
65040234453053
7542550066411
oct122732260371
931650382436
1011130200313
1147a1787261
1221a7594189
131084bb335b
147782c3641
1545220c1e3
hex2976960f9

11130200313 has 4 divisors (see below), whose sum is σ = 14840267088. Its totient is φ = 7420133540.

The previous prime is 11130200311. The next prime is 11130200321. The reversal of 11130200313 is 31300203111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11130200313 - 21 = 11130200311 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11130200292 and 11130200301.

It is not an unprimeable number, because it can be changed into a prime (11130200311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1855033383 + ... + 1855033388.

It is an arithmetic number, because the mean of its divisors is an integer number (3710066772).

Almost surely, 211130200313 is an apocalyptic number.

It is an amenable number.

11130200313 is a deficient number, since it is larger than the sum of its proper divisors (3710066775).

11130200313 is an equidigital number, since it uses as much as digits as its factorization.

11130200313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3710066774.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 11130200313 its reverse (31300203111), we get a palindrome (42430403424).

The spelling of 11130200313 in words is "eleven billion, one hundred thirty million, two hundred thousand, three hundred thirteen".

Divisors: 1 3 3710066771 11130200313