Base | Representation |
---|---|
bin | 10100101110110100… |
… | …11011001100101001 |
3 | 1001201200110211100111 |
4 | 22113122123030221 |
5 | 140243314040403 |
6 | 5040235134321 |
7 | 542550214636 |
oct | 122732331451 |
9 | 31650424314 |
10 | 11130221353 |
11 | 47a17a1049 |
12 | 21a75a43a1 |
13 | 1084bbcac4 |
14 | 7782cb18d |
15 | 45221356d |
hex | 29769b329 |
11130221353 has 4 divisors (see below), whose sum is σ = 11130508548. Its totient is φ = 11129934160.
The previous prime is 11130221339. The next prime is 11130221357. The reversal of 11130221353 is 35312203111.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 9738334489 + 1391886864 = 98683^2 + 37308^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11130221353 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11130221357) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 74326 + ... + 166687.
It is an arithmetic number, because the mean of its divisors is an integer number (2782627137).
Almost surely, 211130221353 is an apocalyptic number.
It is an amenable number.
11130221353 is a deficient number, since it is larger than the sum of its proper divisors (287195).
11130221353 is an equidigital number, since it uses as much as digits as its factorization.
11130221353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 287194.
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 11130221353 its reverse (35312203111), we get a palindrome (46442424464).
The spelling of 11130221353 in words is "eleven billion, one hundred thirty million, two hundred twenty-one thousand, three hundred fifty-three".
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