Base | Representation |
---|---|
bin | 10000001100100101011… |
… | …001100111111111010011 |
3 | 10221101220120000201120011 |
4 | 100030211121213333103 |
5 | 121213433121112201 |
6 | 2211152143055351 |
7 | 143261525635561 |
oct | 20144531477723 |
9 | 3841816021504 |
10 | 1113024004051 |
11 | 39a038041003 |
12 | 15b8655a1557 |
13 | 80c5b132a4b |
14 | 3bc290c0a31 |
15 | 1de44095151 |
hex | 10325667fd3 |
1113024004051 has 2 divisors, whose sum is σ = 1113024004052. Its totient is φ = 1113024004050.
The previous prime is 1113024004019. The next prime is 1113024004109. The reversal of 1113024004051 is 1504004203111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1113024004051 - 25 = 1113024004019 is a prime.
It is not a weakly prime, because it can be changed into another prime (1113024004151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556512002025 + 556512002026.
It is an arithmetic number, because the mean of its divisors is an integer number (556512002026).
Almost surely, 21113024004051 is an apocalyptic number.
1113024004051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113024004051 is an equidigital number, since it uses as much as digits as its factorization.
1113024004051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 480, while the sum is 22.
Adding to 1113024004051 its reverse (1504004203111), we get a palindrome (2617028207162).
The spelling of 1113024004051 in words is "one trillion, one hundred thirteen billion, twenty-four million, four thousand, fifty-one".
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