1113027433 has 4 divisors (see below), whose sum is σ = 1272031360. Its totient is φ = 954023508.

The previous prime is 1113027413. The next prime is 1113027439. The reversal of 1113027433 is 3347203111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1113027433 - 2¹⁷ = 1112896361 is a prime.

It is a super-2 number, since 2×1113027433² = 2477660133221138978, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1113027398 and 1113027407.

It is not an unprimeable number, because it can be changed into a prime (1113027439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79501953 + ... + 79501966.

It is an arithmetic number, because the mean of its divisors is an integer number (318007840).

Almost surely, 2^1113027433 is an apocalyptic number.

It is an amenable number.

1113027433 is a deficient number, since it is larger than the sum of its proper divisors (159003927).

1113027433 is an equidigital number, since it uses as much as digits as its factorization.

1113027433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 159003926.

The product of its (nonzero) digits is 1512, while the sum is 25.

The square root of 1113027433 is about 33362.0657783657. The cubic root of 1113027433 is about 1036.3392724257.

The spelling of 1113027433 in words is "one billion, one hundred thirteen million, twenty-seven thousand, four hundred thirty-three".