Base | Representation |
---|---|
bin | 10000001100100101111… |
… | …100010111111001110001 |
3 | 10221101221012011111222002 |
4 | 100030211330113321301 |
5 | 121213442434110301 |
6 | 2211153110223345 |
7 | 143261666235062 |
oct | 20144574277161 |
9 | 3841835144862 |
10 | 1113033113201 |
11 | 39a0421a2929 |
12 | 15b868654b55 |
13 | 80c5cca1c89 |
14 | 3bc2a3b2569 |
15 | 1de44c9416b |
hex | 10325f17e71 |
1113033113201 has 2 divisors, whose sum is σ = 1113033113202. Its totient is φ = 1113033113200.
The previous prime is 1113033113149. The next prime is 1113033113267. The reversal of 1113033113201 is 1023113303111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1101282336400 + 11750776801 = 1049420^2 + 108401^2 .
It is a cyclic number.
It is not a de Polignac number, because 1113033113201 - 218 = 1113032851057 is a prime.
It is a super-2 number, since 2×11130331132012 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1113033113501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556516556600 + 556516556601.
It is an arithmetic number, because the mean of its divisors is an integer number (556516556601).
Almost surely, 21113033113201 is an apocalyptic number.
It is an amenable number.
1113033113201 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113033113201 is an equidigital number, since it uses as much as digits as its factorization.
1113033113201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 1113033113201 its reverse (1023113303111), we get a palindrome (2136146416312).
The spelling of 1113033113201 in words is "one trillion, one hundred thirteen billion, thirty-three million, one hundred thirteen thousand, two hundred one".
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